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35x^2+65x+30=0
a = 35; b = 65; c = +30;
Δ = b2-4ac
Δ = 652-4·35·30
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-5}{2*35}=\frac{-70}{70} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+5}{2*35}=\frac{-60}{70} =-6/7 $
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